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原帖由 millwood 于 2008-5-30 22:31 发表 
hifi2008, good questions.
I haven't found the addition of R15 to be that beneficial. But it does change the output coupling from voltage coupled to current coupled and some people find that appealing.
1) bootstrap network (R1/R14/C3): this works to increase gain on the phase splitter. It is essentially a passive constant current source. one unique thing bout capacitors is that voltage over a capacitor cannot change suddenly (current going over an inductor cannot change suddenly). So by connecting the left of R14 to the output through C3, the left of R14 goes up and down with the output. the right of R14 also goes up and down with the output, through Vgs of M3 (almost). so in theory, if the left and right of R14 fluctuate together and are identical (almost), there shouldn't be any (ac) current going through R14. Thus, to Q3, R14 has infinite impedance. This greatly increases the gain on Q3.
the amp runs just fine without C3 (thus the boostrap network).
the bootstrap network is also an effective stability tool. As C3 is typically an electrolytic capacitor which turns more resistive than capacitive at high frequencies, the effectiveness of the bootstrap network goes down at high frequencies (typically way out of the audio band), which reduces the open loop gain at high frequencies -> something you want for stability reasons.
Bootstrap'ng is making a come back, and AKSA and P3A, two of the most successful amps of our times, both use such technics.
b) 220u vs. 470u: not much difference. 220u yields less bass but barely noticeable to me.
c) Q3's idle current: R2 and M4's Vgs determines Q3's idle current. I typically set it at least 10x of M4's gate current, which is about 2 - 3ma at 20khz, depending on the mosfets you use. as mosfets typically open up at Vgs = 3.5v, R2=220ohm yields 3.5v/220ohm=15ma. Now, if your mosfets open up at higher (or lower) voltages, you can adjust R2 to get you there.
I will make sure that R15 = R2 if R15 is used - Otherwise, the amp has different gains during the positive and negative cycles.
if R15 isn't used, I will make sure that R14 = R2.
d) what impact does Q3's idle current have? well, if you dial up Q3's idle current, voltage drop over R1/R14 will go up, this will turn off Q1 and M3/M4. so your output DC voltage will go down.
You will need to readjust at least R1 to make sure that M3/M4 idle right.
e) feedback network: the gain is set by 1+R5/R4. Higher R5/R4 will yield better bass response, but will also cause the output voltage to go down (because the voltage drop over R5 will increase). This is also a current feedback amp and they are more stable and have lower noise with lower value feedback resistors. I typically use 110ohm or 220ohm for R4 and then choose R5 based on the amount of gain I need.
How do you set the gain? I typically make sure that with a 1Vp input, the amp is at full power. for linear applications, mosfets typically drop 5 - 6v when "fully" open. so with Vcc=40v, your output swing, peak to trough, is about (40 - 2*5)=30v, or 30v/2=15v peak. This means that your amp needs to have a gain of 15Vp/1Vp = 15x. That means R5=(15-1)*R4=14*110=1.56k max.
you can use smaller resistors and I happen to like 1k resistors.
hope it helps.
hifi2008,一个好问题。
我未发现增加R15那么有效。但它确实将输出耦合由电压耦合改为电流耦合,一些人喜欢这个。
1)自举网络(R1/R14/C3): 增加了分相器的增益。
它实际上是一个无源的常值电流源。
电容的一个特点是它两端的电压不能突变(电感两端的电流不能突变)。(bout->about)
所以通过C3将R14的左端与输出相连,R14左端的电压与输出电压同步变化。
R14的右端同样随输出电压上下变化,叠加了M3的Vgs(几乎,差不多)。
理论上,如果R14两端电压同步变化且几乎一致,不应该有任何(交流)电流通过R14。
这样对Q3而言,R14有无限大阻抗。这大大增加了Q3的增益。
这个放大器没有C3(即自举网络)也能很好工作。
自举网络也是一个有效的稳定工具。因为C3通常是个电解电容,阻抗在高频是会增大,自举网络的效率在高频时下降(通常在音频以外),这就减小了高频时的开环增益,正是稳定性所需要的。
自举是正在重新流行的技术,如AKSA和P3A,两个当今最成功的放大器,都用了这个技术。
b) 220u vs. 470u: 没有太大区别。220u 低频稍欠,但我几乎无法察觉。
c) Q3的静态电流:R2和M4的Vgs决定了Q3的静态电流。
我通常取为M4栅极电流的10倍,在20khz约为2 - 3ma,看你用什么场管,典型的导通 Vgs = 3.5v,取R2=220ohm 得到电流:3.5v/220ohm=15ma。
如果你的场管导通电压不同,调整R2即可。
如果用了R15,我会取R15 = R2。除非放大器正半周的增益与负半周不同。
如果不用R15,我会确保R14 = R2。
d) Q3的静态电流有什么影响?
如果调高Q3的静态电流,R1/R14上的压降会增加,这将使Q1和M3/M4截止,所以输出直流电压会下降。
你需要一个最小的R1,以保证M3/M4的静态正常。
e) 反馈回路:增益取决于 1+R5/R4 。
R5/R4较高会得到更好的低频响应,但会使输出电压降低(因为R5的压降会增加)。
因为这是个电流反馈的放大器,如果反馈回路电阻值较小,会更稳定和更低噪。
R4我通常用110ohm 或 220ohm,再根据需要的增益确定R5的值。
如何设计放大倍数?我通常使得1Vp输入信号时,放大器满功率。
对线性应用,场管的饱和压降可取5 - 6v。所以当Vcc=40v, 你的输出摆幅大约是(40 - 2*5)=30v,或峰值30v/2=15v。这意味着需要的增益为:15Vp/1Vp = 15倍。所以 R5 = (15-1)*R4 = 14*110 = 1.56k (最大)
你可以用更小一点的电阻,我喜欢用 1k。
希望能有所帮助。
感谢millwood提供这么多设计经验,翻译出来希望更多人得到启发。 |
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